0=t^2-3.2t+23

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Solution for 0=t^2-3.2t+23 equation: 



0=t^2-3.2t+23

We move all terms to the left:

0-(t^2-3.2t+23)=0

We add all the numbers together, and all the variables

-(t^2-3.2t+23)=0

We get rid of parentheses

-t^2+3.2t-23=0

We add all the numbers together, and all the variables

-1t^2+3.2t-23=0

a = -1; b = 3.2; c = -23;
Δ = b2-4ac
Δ = 3.22-4·(-1)·(-23)
Δ = -81.76
Delta is less than zero, so there is no solution for the equation

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